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Friday, December 20, 2024

Turnbull Blue: Charge transfer from metal to metal: Colour due CTS :

Ferrous (Fe^+2) salt reacts with potassium ferricyanide to form a blue precipitate which is called Turnbull's blue. The reaction is as follows:

$3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓$

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

Turnbull Blue: [Fe(II)]3[Fe(III)(CN)₆]2

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

3 F e^{2 +} + 2 K_{3} [F e (C N)_{6}] \to F e_{3} [F e (C N)_{6}]_{2} ↓

Related Question:

(1) Although both [Mn(H2O)6]2+ and [FeF6]3- have a d5 configuration and high-spin complexes. But the dilute solutions of Mn2+ and Fe +3 complexes are therefore colorless. Why?

(2) Which of the Complex of the following pairs has the highest value of CFSE?

(3) Colour of Complexes due to charge transfer:

(4) Why violet colour of [Ti(H2O)6]Cl3 disapear (colourless) on heating heating ?

(5) Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 although both have +2 oxidation state and 3d*8 configuration ?

(6) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured ?

(7) Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?

(8) Why all the tetrahedral Complexes are high spin Complexes ?

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