Welcome to Chem Zipper.com......: Which of the Complex of the following pairs has the highest value of CFSE?

Search This Blog

Sunday, January 19, 2020

Which of the Complex of the following pairs has the highest value of CFSE?

(1) [Co(CN)6]3-  and [Co(NH3)6]3+
(2) [Co(NH3)6]3+ and [CoF6]3-
(3) [Co(H2O)6]3+  and [Rh(H2O)6]3+
(4) [Co(H2O)6]2+ and [Co(H2O)6]3+

SOLUTION:
(1)  CN is the stronger ligand than NH3 therefore CFSE of [Co(CN)6]3-  will be more than  [Co(NH3)6]3+
(2) NH3 is stronger ligand than F therefore CFSE of [Co(NH3)6]3+ will be more than [CoF6]3- .
(3) Co belong to 3d series whereas The Rh belong to 4d series. More the value of n more is CFSE therefore CFSE of  [Rh(H2O)6]3+  is more than [Co(H2O)6]3+ .
(4) Oxidation number of Co in [Co(H2O)6]3+ is more than the Oxidation number of [Co(H2O)6]2+  therefore, CFSE of [Co(H2O)6]3+ is more than  [Co(H2O)6]2+ .


Related Questions:

(1) Why all the tetrahedral Complexes are high spin Complexes?

(2) Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?

(3) Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?

(4) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured

(5) Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 is colour although both have +2 oxidation state and 3d8 configuration ?

No comments:

Post a Comment