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The type of overlap in the bridge bond exist in Al2(CH3)6 is

(A) sp3-sp3d-sp3

(B) sp3-sp2-sp3

(C) sp3-s-sp3

(D) sp3-sp3-sp3

Solution: Structure of Al2(CH3)6:

 Answer Key (D)

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Which of the molecule have strongest P=O bond present the given molecules are POF3, POCl3, POBr3 and PO(CH3)3 ?

All the given molecules have same hybridization (sp3) and same central atom (P) the we can apply Bent's rule of hybridization. And according to Bent’s rule more electronegative atoms attach in those hybrid orbital’s which have less s-character or more electronegative atoms decreases s-character and increases p-character.

In case of POF3  fluorine is more electronegative hence s-character  is increase more and more in P=O bond  as compare to other given molecules so P=O bond is shortest in POF3  than others and also increase with decreasing electronegativity.  Hence P=O bond length order is x1 < x2 < x3 < x4  and Bond strength order is reverse of bond length.

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.

Why Bond length of O-O is greater in H2O2 than O2F2?

How to arrange increasing (C-H) bond length in increasing order and H-C-F bond angle in the given compounds, CH4, CH3F, CH2F2 and CHF3 ?

Dipole moment of PCl3F2 molecule is zero while dipole moment of PCl2F3 molecule is non zero why?

Dipole moment of P(CH3)2(CF3)2 molecule is zero while dipole moment of P(CH3)2(CF)3 molecule is non zero why?

How to compare equatorial bond angle (F-S-F) and S-F bond length of SOF4 and SF4 molecules ?

How to compare P=O bond length of POF3, POCl3, POBr3 and PO(CH3)3 molecules?


How to compare P=O bond length of POF3, POCl3, POBr3 and PO(CH3)3 molecules?

All the given molecules have same hybridization (sp3) and same central atom (P) the we can apply Bent’s rule of hybridization. And according to Bent’s rule more electronegative atoms attach in those hybrid orbital’s which have less s-character or more electronegative atoms decreases s-character and increases p-character.

In case of POF3  fluorine is more electronegative hence s-character  is increase more and more in P=O bond  as compare to other given molecules so P=O bond is shortest in POF3  than others and also increase with decreasing electronegativity.  Hence P=O bond length order is x1 < x2 < x3 < x4

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.

Why Bond length of O-O is greater in H2O2 than O2F2?

How to arrange increasing (C-H) bond length in increasing order and H-C-F bond angle in the given compounds, CH4, CH3F, CH2F2 and CHF3 ?

Dipole moment of PCl3F2 molecule is zero while dipole moment of PCl2F3 molecule is non zero why?

Dipole moment of P(CH3)2(CF3)2 molecule is zero while dipole moment of P(CH3)2(CF)3 molecule is non zero why?


How to compare equatorial bond angle (F-S-F) and S-F bond length of SOF4 and SF4 molecules ?


According to Bent's rule lone pair containing hybrid orbital have more s-character than double bond. 

In case of SF4 molecule has sp3d hybridization and one of the equatorial hybrid orbital containing lone pair it means it has more s-character and less p-character while  other remaining  equatorial hybrid orbitals have less s-character and more p-character hence its bond angle decreases and bond length increases.

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.

Why Bond length of O-O is greater in H2O2 than O2F2?

How to arrange increasing (C-H) bond length in increasing order and H-C-F bond angle in the given compounds, CH4, CH3F, CH2F2 and CHF3 ?

Dipole moment of PCl3F2 molecule is zero while dipole moment of PCl2F3 molecule is non zero why?

Dipole moment of P(CH3)2(CF3)2 molecule is zero while dipole moment of P(CH3)2(CF)3 molecule is non zero why?

 


Dipole moment of P(CH3)2(CF3)2 molecule is zero while dipole moment of P(CH3)2(CF)3 molecule is non zero why?

 According to bent’s rule more electronegative atom or group attached those hybrids orbital have minimum s-character.

There is sp3d (Sp2+pd) hybridization trigonal bipiramidal(TBP) geometry in P(CH3)2(CF3)molecule. we known that axial orbital (pd) have no s-character so –CF3  groups are attached with axial positions while –CH3 groups attach with equatorial (Sp2) position. Hence net dipole moment becomes zero. While in case of P(CH3)2(CF)3 molecule one of the –CF3 group is also present at equatorial position hence there is net dipole moment.

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.

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