Yes we can find all possible structural isomers Of a given hydrocarbon.
Number of total structural isomers = 2^(N-4)+1
Where N is number of carbons in hydrocarbon
Example: (1)
Number of structural somers of butane (C4H10) is
SOLUTION:
Where , n=4
=2^(4-4)+1
=2^(0)+1
=1+1
=2
Example: (2)
Number of structural somers of butane (C5H12) is.
SOLUTION:
Where , n=5
=2^(5-4)+1
=2^(1)+1
=2+1
=3
Example: (3)
Number of structural somers of butane (C6H14) is.
SOLUTION:
Where , n=6
=2^(6-4)+1
=2^(2)+1
=4+1
=5
Example: (4)
Number of structural somers of butane (C7H16) is.
SOLUTION:
Where , n=7
=2^(7-4)+1
=2^(3)+1
=8+1
=9
Example: (5)
Number of structural somers of butane (C8H18) is.
SOLUTION:
Where , n=8
=2^(8-4)+1
=2^(4)+1
=16+1
=17
Example: (5)
Number of structural somers of butane (C8H18) is.
SOLUTION:
Where , n=9
=2^(9-4)+1
=2^(5)+1
=32+1
=33