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Showing posts with label EQUIVALENT CONCEPT. Show all posts
Showing posts with label EQUIVALENT CONCEPT. Show all posts

Sunday, June 28, 2020

Vapour density of mixture of NO2 and N2O4 is 34.4 , then percentage abundance (by volume) of NO2 in mixture is .

Molecular weight = 2×VD
                                = 2× 34.5 = 69 u
Consider ℅ of NO2 is "x" then % of N2O4 is "100-x"

Saturday, June 6, 2020

40 gm metal oxide (MO) contain 4 gm of Oxygen.Calculate the equivalent wt of a metal.

40 gm metal oxide contains 4 gm of Oxygen mean it has 36 gm of metal.
Then Equivalent wt of metal is 
  E_m = (Wt of metal/Wt of Oxygen)×8
  E_m = (36gm /4gm)×8
  E_m = 72 gm equivalent

A metal oxide contains 60% metal by mass. The equivalent weight of metal is ..?

Metal Oxide contains 60% metal by mass means 100g of this oxide has 60 g metal and 40g oxygen.

Equivalent Wt of Metal = (Wt of metal/Wt of Oxygen)×8
E_m = 60×8/40 = 12gm equivalent