In given compounds number of ligands, types of ligands and oxidation state is same for central atom belive to same group but different transition series 3d, 4d and 5d respectively. We know that as move top to bottom size of d-orbital(3d--> 4d -->5d) is increases so ligand approches to d-orbitals more closely so the repulsion between d-orbital of metal and ligand is high and splitting energy increases.
Thus order of splitting energy
[Co(NH3)6]3+ < [Rh(NH3)6]3+ < [Ir(NH3)6]3+
Related questions:
(4) What is denticity of NO and NO+ ligands ?
(5) Why all the tetrahedral Complexes are high spin Complexes?
(6)Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?
(7) Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?
(8) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured?
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