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Sunday, May 28, 2023
A 10 liter container consist of 1 mole of gas at 300 K. It is connected to another container having volume 40 liter and is initially at 300 K. The nozzle connecting two containers is opened for a long time and once the movement of gas stopped, the larger container was heated to a temperature of 600 K. Calculate
(A) Moles and pressure of gas in both the containers before heating.
(B) Moles and pressure in two containers after heating. Assume that initially the larger container is completely evacuated.
Saturday, May 27, 2023
A mixture of ethane (C2H6) and ethene (C2H4) occupies 40 litre at 1.00 atm and 400 K , the mixture reacts completely with 130 gm of O2 to produce CO2 and H2O . Assuming ideal gas behaviour , calculate the mole fraction of ethane (C2H6) and ethene (C2H4) in mixture. (R= 0.0821 atm L par mole par kelvin) (IIT 1915)
A mixture of ethane and ethene occupies 35.5 L at 1bar and 405K. The mixture completely reacts with 110 gm of O2 to produce CO2 and H2O. What was the composition of original mixture or what was themoles of ethane and ethene in the mixture (Given R= 0.0821 L atm K^-1mole^-1)
A mixture of ethane and ethene occupies 41L at 1atm and 500K. The mixture completely reacts with 10/3 mole of O2 to produce CO2 and H2O.The mole fractions of ethane and ethene in the mixture are respectively (Given R= 0.0821 L atm K^-1mole^-1)
A solution contains Na 2 CO 3 and NaHCO 3 . 10 mL of the solution required 2.5 mL of 0.1 M H 2 SO 4 for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL of 0.2 M H 2 SO 4 was required. Calculate the amount of Na 2 CO 3 and NaHCO 3 in one litre of the solution.
100mL of a water sample contains 0.81g of calcium bicarbonate and 0.73 of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO 3 is:(molar mass of calcium bicarbonate is 162g mol^−1 and magnesium bicarbonate is 146 gmol −1 )
(A) 1000 ppm
(B) 10000 ppm
(C) 100 ppm
(D) 5000 ppm
Solution :
neq.CaCO3=neqCa(HCO3)2+neqMg(HCO3)2
or
(W÷100) ×2 = (0.81÷ 162)×2 + (0.73÷146)×2
∴w=1.0
∴ Hardness=(1.0÷100) ×10^6=10000ppm
Hence correct option is (B) 10000ppm
25 gm of an unknown hydrocarbon upon burning produce 88 gm of CO2 and 9 gm of H2O. this unknown hydrocarbon contains.
(A ) 18g of carbon and 7g of hydrogen
(B) 20g of carbon and 5g of hydrogen
(C) 22g of carbon and 3g of hydrogen
A mixture of C 3 H 8 (g) & O 2 having total volume 100 ml in an Eudiometry tube is sparked & it is observed that a contraction of 45 ml is observed what can be the
C3H8(g)+5O2(g)→3CO2(g)+4H2O(l)
As par above equation 1 mole of porpane reacts with 5 moles of oxygen to form 3 moles of carbon dioxide.
We know that the number of moles is directly proportional to the volume of the gas.
Thus when 15 ml of propane reacts with 75 ml of oxygen, 45 ml of carbon dioxide will be obtained.
The contraction in the volume will be 15+75−45=45ml.
This is possible when the composition of the reacting mixture is either 15ml C3H8 and 85ml O2 or 25ml C3H8 and 75ml O2.
Hence, options A and B are the correct answers.
Friday, May 26, 2023
Thursday, May 25, 2023
A certain electronic transition from an excited state to Ground state of the Hydrogen atom in one or more steps gives rise to 5 lines in the ultra violet region of the spectrum.How many lines does this transition produce in the Infra red region of the spectrum?
Find out the ratio of the moles of hydrogen and carbon dioxide obtained after 6 successive effusion step initially present in 1:1 molar ratio
Answer Key: 22^6
Friday, May 19, 2023
5.7 g of bleaching powder was suspended in 500 mL of water. 25 mL of this suspension on treatment with KI and HCl liberated iodine which reacted with 24.35 mL of 10N Na2S2O3. Calculate the percentage of available chlorine in bleaching powder.
Answer Key: 30.33 %
Thursday, May 18, 2023
A metal carbonate on heating is converted to metal oxide and is reduced to 60% of its original weight. The equivalent weight of the metal is
Answer Key: 25
Sunday, May 14, 2023
A plant virus is found to consist of uniform cylindrical particle of 150 Angstrom in diameter and 5000 Angstrom long. The specific volume of the virus is 0.75 mL g−1. if the virus is considered to be a single particle, find its molar mass.
Answer key : 7.092×10^7
Wednesday, May 10, 2023
Friday, May 5, 2023
The Normality of 4.9% (w/w) H2SO4 solution having density .02 gm/ml is ?
Ans key: (1.02 N )
Wednesday, May 3, 2023
Henry`s law is not applicable for the aqueous solution of.......
(A) O2
(B) N2
(C) SO3
(D) He
Answer (C)
Explanation: Henry`s law is not applicable for the aqueous solution of those gas which undergoes chemical reactions with solvent (water).
Here SO3 react with water to form sulphuric acid.
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