MOLE-MOLE ANALYSIS:

Mole Concepts:

Mole and Moles Analysis rule:

Ratio of Moles of reactant or product with its coefficient is always constant for a balance chemical equation:

ILLUSTRATIVE EXAMPLE (1):

ILLUSTRATIVE EXAMPLE (2):

ILLUSTRATIVE EXAMPLE (3):

ILLUSTRATIVE EXAMPLE (4):  367.5 gm KClO₃ (122.5) when heated then calculate.

(1) How many gram of O₂ is produced?

(2)How Many litre of O₂ is produced at STP?

SOLUTION:

ILLUSTRATIVE EXAMPLE (5): how many moles O₂ are required to needed produced 5 moles of Fe₂O₃.

SOLUTION:

ILLUSTRATIVE EXAMPLE (6): how many grams of Fe₂O₃ formed by heating of 18 gm FeO with O₂.

SOLUTION:

PERCENTAGE(%) YIELD OF CHEMICAL REACTION:

ILLUSTRATIVE EXAMPLE (1): 200 gm of CaCO₃ on heating produces 11.2 litre of CO₂ (g) at STP calculate % yield of reaction?

ILLUSTRATIVE EXAMPLE (2): 3.9 gm Al(OH)₃  is reacted with excess of HCl , 6.5 gm AlCl₃ is formed determined % yield of reaction ?

ILLUSTRATIVE EXAMPLE (3): Calculate moles of D produce by 4 moles of A.

ILLUSTRATIVE EXAMPLE (4): 9 moles of D and 14 moles of E are allowed to react in closed vessel according to given equation.

Calculate number of B formed in end of reaction, If 4 moles of G are present in reaction vessel. (% yield of each reaction in the reactions)

ILLUSTRATIVE EXAMPLE (5): For the reaction
Initially 2.5 moles of Fe(NO₃)₃ and 3.6 moles of Na₂CO₃ are taken. If 6.3 moles of Na₂CO₃ is obtained the % yield of given reaction is ?