Why are 2p orbitals higher in energy than 2s?

The energy of atomic orbitals depends upon principal as well as azimuthal quantum number, which is  more common known as (n+l) rule .
According to (n+l) rule the atomic orbital has less (n+l)  value also has less energy vice versa.
For 2S => n= 2, l=0,. =>n+l= 2+0=2
For 2p => n= 2, l=2,. =>n+l= 2+1=3
Hence 2p have more energy than 2s orbital

Does 2s and 2p have the same energy?

'NO' the energy of atomic orbitals depends upon principal as well as azimuthal quantum number, which is  more common known as (n+l) rule .

According to (n+l) rule the atomic orbital has less (n+l)  value also has less energy vice versa.

For 2S => n= 2, l=0,. =>n+l= 2+0=2

For 2p => n= 2, l=2,. =>n+l= 2+1=3

Hence 2p have more energy than 2s orbital