Given % labelling (X)=109% and 115% ,finddifference between weight of free SO3 in these samples ?.
Difference between weight of free SO3 in these samples are= 66.66-44= 26.67 gm
Sunday, April 19, 2020
If the percentage free SO3 in an Oleum sample is 20% then label the sample of Oleum in term of percentage H2SO4.?
Percentage labelling of oleum Calculate as:
Calculate the % of free SO3 in an Oleum sample that is labelled as 118 % ?
We can calculate % labelling by Stoichiometric calculation as:
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