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Sunday, October 11, 2020

How to calculate % free SO3 in given Oleum sample ?

CALCULATIONS OF FREE SO3 IN (X%) OLEUM SAMPLE :
Given - X %  labelled 100 gm Oleum,it means  (X-100) gm water required to destroyed all free SO3present in 100 gm Oleum.
                                               
WH2O= (X-100) gm
BY STOICHIOMETRIC CALCULATION:
Weight of SO= nSO3 X Molecular wt SO3

Weight of H2SO= nH2SO4 X Molecular wt of H2SO4
 
thus % (Free) SOpresent in 100 gm 109% labelled Oleum Sample is

What is the maximum % labelling of Oleum sample ?

For maximum possible labbelling amount of SO3 is 100 gm, It means 100 gm Oleum sample contains 100 gm SO3 only and zero( 0 )gm H2SO4 ,hence maximum labbelling possible is 122.5 %.