Calculate the pH of 1.0×10^−3 M sodium phenolate NaOC6​H5​ . Ka​ for C6​H5​OH is 1×10^−10 .

ΔG^ o at 25^°C for the reaction 1/2N2(g) + 3/2H2(g) ⇋ 2NH3(g) is -11.392 kj mole^-1. Hence thermodynamics equilibrium constant is : he equilibrium constant for reaction is 10. (Use R=8.3 JK ^−1 mol ^−1)

Answer key : 10^2

The dissociation equilibrium of a gas AB2 can be represented as : 2AB2(g) ⇋ 2AB(g) + B2(g) The degree of dissociation is "x" and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure P is.

(A) (2KP/P)^1/2  

(B) (KP/P) 

(C) (2KP/P) 

(D) (2KP/P)^1/3