N(CH3)3 is pyramidal while(SiH3)3N is trigonal planer why?

N(CH₃)₃ has sp3 hybridization & pyramidal shape at N, but in (SiH₃)₃N again there is 2pπ—3dπ back bonding between lone pair orbital of nitrogen into vacant orbital of silicon. Hence trisilyl amines is sp2, planer & is less basic than trimethyl amine.

Calculate the percentage degree of dissociation of an electrolyte XY2 ( normal molar mass=165) in water if the observed molar mass by measuring elevation in boiling point is 65.5.

Which of the following pair of solution (aq.) contain isotonic solution at same temperature? (Assume 100 % ionisation of electrolytes) (1) 0.1 M NaCI and 0.2 M CaCI2(2) 0.1 M NaCI and 0.3 M AICI3 (3) 0.3 M NaCI and 0.1 M AICI3 (4) 0.3 M NaCI and 0.2 CaCI2

Freezing point of pure liquid A is T K. If some amount of non-electrolyte non-volatile impurity is added in A, an ideal solution is formed. On cooling at 200 K, only 30% (by mass) liquid A is present and at 201 K, 60 % (by mass) liquid A is present. The value of T is .

Liquid A and B form ideal solution at temperature T. Mole fraction of A in liquid and vapour phase are 0.4 and 4/13 respectively, when total pressure is 130 torr. The vapour pressure (in torr) of A and B in pure state at temperature T are respectively.

We know that partial pressure of components of a binary solution containing A and B component.

(1) In liquid state:

P_A= P°_A X_A and  P_B= P°_B X_B

(2) In Vapour phase: 

P_A= P_T Y_A  and P_B= P_T Y_B

Where X_A and X_B is mole fraction in liquid state while Y_A and Y_B is mole fraction in vapour phase