For the galvanic cell: Ag|AgCl(s)| KCl (0.2M) || KBr (0.001M) |AgBr(s) |Ag : calculate the e.m.f. generated and assign correct polarity to each electrode for a spontaneous process after taking an account of cell reaction at 25°c. [Given Ksp(AgCl) = 2.8×10^-10 and Ksp(AgCl) = 3.3×10^-13]

Thus to get positive cellphone potential (Ecell) , the polarity of the cell should be reversed i.e cell is represented as 

Ag(s)|AgBr(s)| KBr(0.002M) || KCl (0.2M)|AgCl(s)|Ag(s):

Where 

Ag(s)|AgBr(s)| KBr(0.002M) act as Anode while KCl (0.2M)|AgCl(s)|Ag(s): act as cathode

How to determine anode and cathode of concentration cell instead of both electrodes are same ?

Important thing :

For concentrated cell both electrodes are same so E not cell is always zero  and Qc is always less than one.

You should first assume any one is the cathode and the other one  is the anode. Then you can calculate the theoretical emf:

(1)  If the emf > 0, then that reaction will be spontaneous and it means you got the right cathode and right anode.

 (2) If the calculated emf < 0, it means that that reaction is not spontaneous, which means that the reverse reaction is spontaneous; that happens if you exchange the cathode and anode

The conductivity of 0.0011028 mol per liter acetic acid is 4.95 × 10–5 S per cm. Calculate its dissociation constant if ^°m for acetic acid is 390.5 S cm2 per mol–1 .

An aqueous solution has 5% urea and 10% glucose by weight. what will be the freezing point of this solution ? ( Kf = 1.86 K Kg per mole)

The vapour pressure of two pure liquids A and B, that form an ideal solution are 100 and 900 torr respectively at temperature T. This liquid solution of A and B is composed of 1 mole of A and 1 mole of B. What will be the pressure, when 1 mole of mixrure has been vaporized?