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Thursday, October 1, 2020
1 mole of a real gas is subjected to a process from (2 bar, 40 lit.,300K) to (4 bar, 30 lit., 400 K). If change in internal energy is 35 kJ then calculate enthalpy change for the process.
D
H =
D
U +
D
(PV)
D
(PV) = P
2
V
2
– P
1
V
1
= 4 × 30 – 2 × 40
= 40 liter -bar = 4 kJ
so
D
H = 35 + 4 = 24 kJ
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