If the mole fraction of a solute is changed from 1/4 to 1/2 in the 800 gm of solvent . then the ratio of molality will be .

The mole fraction of glucose in aqueous solution is 0.2 , The molality of solution will be.

Calculate the mole fraction of solute in the 12 molal aqueous solution of CaCO3.

40 gm metal oxide (MO) contain 4 gm of Oxygen.Calculate the equivalent wt of a metal.

40 gm metal oxide contains 4 gm of Oxygen mean it has 36 gm of metal.

Then Equivalent wt of metal is 

  E_m = (Wt of metal/Wt of Oxygen)×8

  E_m = (36gm /4gm)×8

  E_m = 72 gm equivalent

A metal oxide contains 60% metal by mass. The equivalent weight of metal is ..?

Metal Oxide contains 60% metal by mass means 100g of this oxide has 60 g metal and 40g oxygen.

Equivalent Wt of Metal = (Wt of metal/Wt of Oxygen)×8

E_m = 60×8/40 = 12gm equivalent