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### 9 gm water is added into Oleum sample labelled as 112% H2SO4 then the amount of free SO3 remaining in the solution is ? (STP=1atm and 273K).

SOLUTION: Initial free moles of SO3=  =2/3 moles
Moles of water that combined with free moles of SO3=9/18=1/2 moles
Moles of free SOleft 2/3-1/2=1/6 moles
Volume of free SOat STP=1/6X22.4=3.73 L