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A non Stoichiometric oxide of iron represented as Fe_x O_1.0 , contains one Fe+3 for every three Fe+2 ions , then find the value of x is...

Given that one Fe+3 for every Fe+2 and total ions of Fe+3 and Fe+2 is equal to "x"  then number of Fe+3 is x/4 and Fe+2 is equal to 3x/4.
Finally we can calculate the value of x by balancing Oxidation state of Compound, given as :