Fe0.94 O 1.0 is non stachiometric compound hence Nickel contains both Fe+2 and Fe+3 .
We can calculate ℅ presence of Fe+2 and Fe+3 by oxidation method.
(F+2+Fe+3) O1.O
2x+3(0.94-x)-2=0
Fe+2=x=0.82 or 82% and Fe+3= 8%
Search This Blog
Subscribe to:
Post Comments (Atom)
Featured Post
STRUCTURE OF FULLERENCES :
(1) A fascinating discovery was the synthesis of spherical carbon-cage molecules called fullerences. The discovery of fullerene was awarde...
Top Search Topics
-
Bleaching powder is not a true compound but it is a mixed salt of calcium hypochlorite [Ca (OCl) 2 ].3H 2 O and basic calcium chloride [C... -
The structure of crystalline solids is determined by packing of their constituents .In order to understand the packing of the constituen... -
(1) Back bonding is a type of weaker π bond which is formed by sideways overlapping of filled orbital with empty orbital present on adjace... -
Phosphorous is a pentavalent element hence show +3 and +5 oxidation state (d orbital presence).it form two oxide P 2 O 3 (+3) and P 2 O 5... -
We know that the Ligands which cause large degree of crystal filed splitting are termed as strong field ligands. and Ligands that cause onl... -
(1) Oleum can be represented by the formula ySO 3 .H 2 O where y is the total molar sulphur trioxide content .the value of y can be va... -
Pyrrole, furan and thiophene undergo electrophilic substitution reactions like nitration, sulphonation, halogenation etc. characteristic ... -
In case of Pyrrole the lone pair electrons of the nitrogen atom is involved in conjugated system of pi electrons of five membered ring ... -
[FeF 6 ] 3- is a Fe (III) complex hence [Ar] 3d 5 . F - is a weak field ligand and the complex is high spin: ... -
Tetahedral complex (sp 3 ): In a tetrahedral field : Consider a cube such that a metal atom or ion is situated at its centre of symmetry ...
No comments:
Post a Comment