Fe0.94 O 1.0 is non stachiometric compound hence Nickel contains both Fe+2 and Fe+3 .
We can calculate ℅ presence of Fe+2 and Fe+3 by oxidation method.
(F+2+Fe+3) O1.O
2x+3(0.94-x)-2=0
Fe+2=x=0.82 or 82% and Fe+3= 8%
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