Search This Blog
A sample of butane gas C4H10 of unknown mass is contained in a vessel of unknown volume V at 25oC and a pressure of 760 mmHg. To this vessel 8.6787 g of neon gas is added in such a waythat no butane is lost from the vessel. The final pressure in the vessel is 1920 mm Hg at the same temperature. Calculate the volume of the vessel and the mass of butane.
Subscribe to:
Post Comments (Atom)
Featured Post
Structure of “Borazine/Borazole”/inorganic Benzene:
(1) Borazine is an inorganic compound with the chemical formula (B 3 N 3 H 6 ). and also called Borazole. It is a heterocyclic compound,...
Top Search Topics
-
Bleaching powder is not a true compound but it is a mixed salt of calcium hypochlorite [Ca (OCl) 2 ].3H 2 O and basic calcium chloride [C... -
The structure of crystalline solids is determined by packing of their constituents .In order to understand the packing of the constituen... -
(1) Back bonding is a type of weaker π bond which is formed by sideways overlapping of filled orbital with empty orbital present on adjace... -
Phosphorous is a pentavalent element hence show +3 and +5 oxidation state (d orbital presence).it form two oxide P 2 O 3 (+3) and P 2 O 5... -
We know that the Ligands which cause large degree of crystal filed splitting are termed as strong field ligands. and Ligands that cause onl...
Why there is p =760/760=1atm
ReplyDeletewe use pressure in Atm but given is in mm hg so convert into Atm and (1 Atm = 760 mm hg)
Delete