A column of mercury of 10cm length is contained in the middle of a narrow horizontal 1m (100cm) long tube which is closed at both the ends. Both the halves of the tube contain air at a pressure of 76 cm of mercury. By what distance will the column of mercury be displaced if the tube is held vertically?

 

Initially when tube is horizontal then pressure (P) =76 cm Hg and volume (V) =45 cm of tube.

Finally when tube is made vertical, as temperature and pressure are constant, then by gas law

P₁ (45+x)=PV   ……..(1)

(P₁+10)(45-x) =PV……(2)

From equations 1 and 2 find the value of P₁

P₁ =(225-5x)/x

Put the value of P₁ in equation 1 or 2

On calculating the value of x is 2.95 cm

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