Given Area = 80 cm3
Thickness = 0.0005 cm
Density= 10.5 gl cm3
Thus Mass of silver deposited on cathode is = 80 cm3 x 0.0005
cm x10.5 gm/cm3= 0.42 gm
Given Area = 80 cm3
Thickness = 0.0005 cm
Density= 10.5 gl cm3
Thus Mass of silver deposited on cathode is = 80 cm3 x 0.0005
cm x10.5 gm/cm3= 0.42 gm
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