The electronegativity of F and H are 4.0 and 2.1 respectively. The percentage ionic character in H and F bond is.

The percentage ionic character in covalent compound arises due to the electronegative difference of bonding atoms. And percentage ionic character of covalent bond calculates by Henry and Smith equation;

Solved Questions:

(2) A given compound AB whose electronegative difference is 1.9 . Atomic radius of A and B are 4 and 2 Angstroms the distance between A and B means dA-B is ?

(2) The C–C single bond length is 1.54 Angstroms and that of Cl–Cl is 1.98 Angstroms. If the electronegativity of Cl and C are 3.0 and 2.5 respectively, the C–Cl bond-length will be equal to ?

(3) Stevenson & Schromaker Equation: Determination covalent radius of Heterogeneous Molecules.

(4) How to calculate percentage (%) ionic character in covalent compounds?

Related Questions:

(1) The electronegativities of B, Al, Ga are 2.0, 1.5, 1.6 respectively. The trend is not regular. Explain.

(2) Li2CO3 decomposes on heating but other alkali metal carbonates don’t. Explain.

(3) Of all noble metals, gold has got a relatively high electron affinity. Explain.

(4 Ionization energy of Boron is smaller than Beryllium even though effective nuclear charge is higher?

(5) What are the increasing order of ioni radii of first group elements in water ?

(6) What are the increasing order of molar conductivity of first group elements in water ?