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Sunday, May 26, 2019

KINETICS OF ZERO ORDER REACTIONS:

Consider a general chemical reaction its follow zero order kinetics
[A] 0 =initial concentration of reactant A
[A]t = concentration of after time t
[B]t = concentration of product B after time t
On Integration of above equation:
On rearrangement equation (1) give equation of straight line
Note: Concentration of reactant after regular interval of time will constitute an arithmetical progression (AP) 

Similarly concentration of product B after time t

Unit of rate constant:    K= Mol/litre second
Half life period:  Time required converting half of the reactant to product i.e. life of zero order reaction may give as

Imp note: In zero order reaction average rate of reaction is equal to instantaneous rate of reaction
100% completion of time: It is time in which reactant completely converted into product.

ILLUSTRATIVE EXAMPLE (1): The graph show decomposition of Ammonia  on Pt surface it initial concentration of ammonia is 0.1 M then calculate the time required for the 40% completion of reaction.
SOLUTION:   
ILLUSTRATIVE EXAMPLE (2): A certain zero order reaction has k=0.025 M /S for disappearance of A what will be the concentration of  A after 15 second if initial concentration is 0.5 M?
SOLUTION: concentration of A after time of t is [A]t

Saturday, May 25, 2019

KINETICS FOR nth ORDER REACTION:

Consider a chemical reaction have one reactant only
Differential rate expression may be written as:
Separating same variable same side
On integrating by rule
By equation (1) and (2)
Graphical representation:

Half life period:
Graphical representation:
Note : This formula do not valid for n=0 and n=1

ILLUSTRATIVE EXAMPLE (1) :  A graph plotted between log  t50   Vs log conc. (a)  is a straight line what conclusion withdraw from the given graph?
SOLUTION: for a given reaction

ILLUSTRATIVE EXAMPLE (1) :  What  will be the order of reaction and rate constant for a chemical change having log  t50   Vs log conc. (a)  curve as

SOLUTION: for a given reaction
Case (1) n=2 i.e.    2nd order chemical kinetics:
Graphical representation: 


Half life period:
Graphical representation:

Case (2) n= 3 i.e.    3nd order chemical kinetics:
Graphical representation:

Half life period:

Graphical representation:
Important kinetic expression for reaction of type as:
Graphs of various order:
W h e r e
[A]0 = initial concentration
[A] = concentration at time t
t1/2 = time taken for initial concentration of reactant to finish by 50%
t 3/4 = time taken for initial concentration of reactant to finish by 75%