The oxides having number of oxygen atoms per atom is found to be 3÷2 = 1.5 . It may be ionic, covalent, or mixed oxide.
Examples:
(1) Covalent: B2O3, N2O3
(2) Ionic: Al2O3, Fe2O3
(3) Mixed: Pb2O3 (PbO +PbO2)Related Questions:
Friday, February 7, 2020
Arrange in increasing order of extent of hydrolysis [ CCI4, MgCI2, AICI3, PCl5, SiCI4].
We know that CCI4 does not undergo hydrolysis since "C" does not have d orbital. The central atom of all other element contains empty d-orbitals and hence undergoes hydrolysis. As the oxidation state of the central atom increases from +2 (MgCI2) to +3 (AICI3) to +4 (SiCI4) to +5 (PCl5), the extent of hydrolysis increases accordingly. Thus, the overall increasing order of extent of hydrolysis follows the order:
["CCI4 < MgCI2 < AICl3 < SiCl4 < PCl5"]
Related Questions:
Although Sulphur contain vacant d-orbital but SF6 does not under go hydrolysis. Why ?
In SF6 Sulphur atom contain vacant d-orbital but SF6 does not undergo hydrolysis because Sulphur is sterically protected (Crowding) by six fluorine atoms and water molecules are unable to co-ordinate with vacant d-orbital of sulphur atom. Down the group in Suphur family extent of Hydrolysis increases due to increasing of size of central atoms crowding decrease. The order is as
[" SF6 < SeF6 < TeF6 "]
Related Questions:
(1) What are the SESQUI OXIDES ? give the examples.
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