Calculate the Zeff (Z*) for 3d electrons of chromium atom (Slater's Rule)?

Step (1): Write the electronic configuration of Chromium (Cr) in the appropriate form.

Cr: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ 

Cr: (1s²)(2s²,2p⁶)(3s²,3p⁶,3d⁵)(4s¹)

Step (2): Use the Slater Rule to calculate the shielding constant for the electron.

Note: And ignore the group of electron to the right of the 3d electrons, these electrons do not contribute to the shielding constant.

(S)_3d = (4s electrons)x ignore + (valence  electrons (3d)-1) x 0.35 +(remaining electrons) x 1.00

(S)_3d = (5-1)x 0.35+ (18)x 1.00  = 19.4

                      Thus Z* =Z-S = 24-19.4 = 4.6

Related Questions:

(1) Calculate the Zeff (Z*) for 4s electron of chromium atom (Slater's Rule)?

(2) What is the shielding constant (S) experienced by a 3d electron in the bromine atom?

(3) Total numbers of elements which are liquid at normal temperature is ?

(4) What is Mendeleev's periodic table ? give important features and draw back of Mendeleev's table.

(5) What is atomic density ? give the periodicity of atomic density in periods and groups.

(6) What is atomic volume ? and what is periodicity of atomic volume in groups and periods ?

(7) Why there are 2, 8 and 8 elements in first, second and third periodic of periods table respectively ? Explain.

(8) In alkali metal group which is the strongest reducing agent in aqueous solution and why?

(9) The electron affinity of sulphur is greater than oxygen. Why?

(10) The first ionization energy of carbon atom is greater than that of boron atom, whereas reverse is true for the second ionization energy. Explain.

Calculate the Zeff (Z*) for 4s electron of chromium atom (Slater's Rule)?

 Step (1): Write the electronic configuration of Chromium (Cr) in the appropriate form.

Cr: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ 

Cr: (1s²)(2s²,2p⁶)(3s²,3p⁶,3d⁵)(4s¹)

Step (2): Use the Slater Rule to calculate the shielding constant for the electron.

 (S)_4S = (4s electrons-1)x 0.35+ ( electrons of penultimate shell)x 0.85 +(remaining electrons) x 1.00 

(S)_4s = (1-1)x 0.35+ (13)x 0.85+ (10)x 1.00 = 21.05

                                   Thus Z* =Z-S = 24-21.05 = 2.95

What is the shielding constant (S) experienced by a 3d electron in the bromine atom?

Related Questions:

(1) What are the Amphoteric metals ? gives Examples.

(2) Name of total metalloids present in periodic table ?

(3) Total numbers of elements which are liquid at normal temperature is ?

(4) What is Mendeleev's periodic table ? give important features and draw back of Mendeleev's table.

(5) What is atomic density ? give the periodicity of atomic density in periods and groups.

(6) What is atomic volume ? and what is periodicity of atomic volume in groups and periods ?

(7) Why there are 2, 8 and 8 elements in first, second and third periodic of periods table respectively ? Explain.

(8) In alkali metal group which is the strongest reducing agent in aqueous solution and why?

(9) The electron affinity of sulphur is greater than oxygen. Why?

(10) The first ionization energy of carbon atom is greater than that of boron atom, whereas reverse is true for the second ionization energy. Explain.

Structure of Black phosphorus:

(1) Black phosphorous  is thermodynamically most stable allotropes of phosphorous.

(2) It exist in the form of hexagonal layers like graphite.

(3) It is less reactive and has maximum density.

(4) It is conductor of electricity like graphite.

(5) It has two form alpha Black phosphorous and Beta Black phosphorous.

(6) Alpha Black phosphorous is formed when red phosphorous is heated in a sealed tube at 803 K. It can be sublimed in air and has opaque Monoclinic or rhombohedral crystal. It does not oxidized in air.

(7) Black phosphorous exist as solid of high density.

(8) The order of stability:

                         Black (P) > Red (P) > White (P)

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Which is more basic N(CH3)3 or N(SiH3)3 , explain?

Trisilyl amine, N(SiH3)3 is planar whereas trimethyl amines N(CH3)3 is pyramidal. Explain why?.