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Sunday, February 9, 2020

What are the structural difference between oxides ( P4O6 and P4O10) of phosphorous?

According to “Bent Rule” loan pair prefer to stay to in those atomic orbital have more (S) character. And bond length is directly proportional to p-character. 

(1) In case of P4O6 molecules atomic orbital containing loan pair have more (s)-character and less (P) character hence shorter bond length while remaining orbitals have less (S) character and more (P) character hence longer bond length (X1) than (X2) in P4O10 .

(2) We know that On increasing % s character in hybrid orbital, the bond length decreases while bond angle increases.

(3) In Case of P4O6   (O-P-O) bond is Smaller due to higher P character in atomic orbital than orbital containing (O-P-O) in P4O10(have more s-character )

For reading more Details about  click on  Bent Rule andDrago's rule

Related Questions:

What is Bent’s rule of hybridization?

Which of the following compound have longest (S=O)bond length , O=SF2, O=SCl2, O=SBr2.


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