Are all the five bonds of PCl5 equivalent? Justify your answer.

Special note for PCl5: 

In PCI₃, there are two types of bonds-Two (P-Cl) axial bond and three (P-CI) equatorial bonds.

Due to repulsion between Cl atom: (P-Cl) axial bonds are longer in bond length (240 pm) and are weaker while (P-Cl) equatorial bonds are shorter in bond length (202 pm). So, PCl5 on heating gives

         PCI,5 --- PCl3 + Cl2

Is All the I-F bond are equal in IF7 molecule?

In IF, there are two type of bonds. 

Two (I-F) axial bonds and 5 (I-F) equatorial bonds. 

Five (I-F) bonds are at 72° and have more repulsion than two (I-F) bonds which are at 90°. 

Thus, five (I-F) equatorial bonds are longer in bond length and are weaker, thus on heating five (I-F) equatorial bond breaks.