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Saturday, January 11, 2020

How to write dehydration and ring expansion mechanism of 1-(1-cyclopentyl) methanol?

How to write dehydration and ring expansion mechanism of Tetrahydrofurfuryl alcohol?

How to write dehydration and ring expansion mechanism of 2-cyclopentylethanol?

Friday, January 10, 2020

Why do not Friedel-Crafts reactions succeed on aromatic rings that are substituted either by a strongly electron-withdrawing group such as carbonyl (C=O) or by an amino group (-NH2, NHR, -NR2):


We Know that acyl groups or any electron withdrawing group present at ring which deactivating as result further substitution does not take place

While in case of Aniline or its derivatives, the Friedel Craft reaction occurs in the presence of aluminium chloride which is Lewis acidic and the Aniline is a strong base. Therefore, when aniline is reacted with aluminium chloride in Friedel-Craft’s reaction, formation of salt takes place. On which the presence of positive charge on nitrogen deactivates the benzene ring towards electrophilic aromatic substitution reactions. Therefore, aniline does not undergo Friedel-Craft’s reaction


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Why does not aniline undergo Friedel crafts reactions explain?


We know that the Friedel Craft reaction occurs in the presence of aluminium chloride which is Lewis acidic and the Aniline is a strong base. Therefore, when aniline is reacted with aluminium chloride in Friedel-Craft’s reaction, formation of salt takes place. The  salt formation take place as:


The presence of positive charge on nitrogen deactivates the benzene ring towards electrophilic aromatic substitution reactions. Therefore, aniline does not undergo Friedel-Craft’s reaction.

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