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Saturday, May 23, 2020

What are structural information of Dimomd ?

Diamond structure is ZnS type structure  in which carbon atoms forms  a face centred cubic (FCC/CCP) lattice as well as  four out of eight (50%) or alternate tetrahedral voids are occupied by carbon atoms. Every atom in this structure is surrounded tetrahedrally by four other. No discrete molecule can be discerned (identified) in diamond .the entire crystal is giant molecule a unit cell of which is shown as below.

Note : Only those atoms which form four covalent bond produce a repeated 3D structure using only covalent bonds.

Lattice of Diamond is ZnS type structure.

(1) C- form FCC/CCP (4-atoms)

(2) C- atoms present at the (50%) alternative tetrahedral voids (4-atoms)

(3) Total Number of one lattice unit is eight (8) hence molecular formula of diamond is (C8) (i.e. Z= 8)

(4) Number of C-C bond in lattice cell is = 4×4= 16

(5) Number of C-C bond per carbon atom is 16/8=2

(6) The distance between two Corbin atom is dC-C = a√3/4 and the radius of carbon atom = dc-c/2 = rc = a√3/2x4

(8) Packing efficiency (PE = π√3/10= 0.34 or 34%):

(9) Voids = 66 % 

Additional Information: 


Related Questions:

What are the normal spinel structures?

What are the inverse spinel structures?

How to calculate radius ratio of square Voids?

How to calculate radius ratio triangular voids?

How to calculate packing fraction or packing efficiency of two dimensional (2D) hexagonal packing solid atoms?

The coordination number of Al in the crystalline state of AlCl3 is .... (IIT-JEE 2009)

The number of hexagonal faces that are present in truncated octahedron is .... (IIT-JEE 2011)

What are structural information of Dimomd ?

In diamond, carbon atoms occupy FCC/CCP lattice point as well as alternate tetrahedral voids. If edge length of unit cell is 3.56pm, the radius of carbon atom is ?



2 millimolar solution of sodium ferrocyanide is 60% dissociated at 27°C. osmotic pressure of the slotution is .

Given that 2 millimolar solution of sodium ferrocyanide (Na4[Fe(CAN)6] ) is 60% dissociated at 27°C.
First find van't Hoff facter's (i) than Calculate osmotic pressure (π)= icRT as follow:

Friday, May 22, 2020

Decimolar solution of K4[Fe(CN)6] dissociate by 60% at 27°C. Determine osmotlc pressure in Nature/M2.

We know that osmotlc pressure is equal to the (π) = iCRT then  first Calculate the value of(i) then osmotlc pressure.

A complex is represented as CoCl3.xNH3.Freezing point of its 0.1 molar solution is - 0.558° C (Kf = 18.6) Assuming 100 % dissociation and coordination number of Co(iii) is six , the what is the complex formula ?

We can find the formula of Complex by :

A complex is wrltten as M(en)y.xBr. lts 0.05 molar solution shows 2.46 atm osmotlc pressure at 27°C. Assuming 100 % ionisaton and coordination number of metal (iii) is six, complex may be:

The Complex is M(en)y.xBr. and given c= 0.05 M, osmotlc pressure = 2.46 atm and The= 300K.

We know that osmotlc pressure (π)= icRT
Where To is universal gas constant = 0.0821j/mole per K
Then I = π/ cRT = 2.46/0.05×0.0821×300
                           =2 
  The vant Hoff facter's is (2) means their is two ions furnish after dissociation of Complex since  coordination number is (6) and van't hoff facter is (2) then formula of Complex is :
[M(en)2Br2]Br --> [M(en)2Br2]+  +Br-