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Tuesday, December 8, 2020
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Monday, December 7, 2020
The stop-cock connecting the two bulbs of 5dm3 and 10dm3 contains an ideal gas at 10 bar and 10 bar respectively is opened. Thus final pressure if two bulbs opened at the same temperature is
At constant temperature
P1V1+P2V2
=PR(V1+V2)
5x10 +10x5 =
PR(5+10)
PR=
100/15 =6.67 bar.
Related Questions;
Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure Pi and temperature Ti are connected through a narrow tube of negligible volume as shown in the figure below. The pressure of one of the bulb is raised to T2. The final pressure is: (JEE Mains-2016)
Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure Pi and temperature Ti are connected through a narrow tube of negligible volume as shown in the figure below. The pressure of one of the bulb is raised to T2. The final pressure is: (JEE Mains-2016)
Initially both
bulbs are under similar condition hence number of moles of gas in each
container
Total number
of moles in both bulbs;
When temperature of one of the bulb is increases from T1 toT2 then final pressure Pf and number of moles.
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