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Thursday, June 24, 2021

What is the Isoelectric points of amino acids?

Isoelectric point (pI): The hydrogen ion concentration at which a particular amino acid does not influence by electric field is known as Iso-electric point (pI).
At isoelectric points:
(1) [cation] = [Anion]
(2) Net charge on particular amino acid is zero.
(3) Maximum concentration of zwiter ion
(1) Isoelectric point (pI) of neutral amino acid (for example alanine) is the average of pKa1 and pKa2. For example pI of alanine calculated as:
          PI= 1/2(pKa1+pKa2)
(2) Isoelectric point (pI) of acidic amino acid is the average of pKa values of two -COOH groups (uncharged) in its acidic form. For example pI of Glutamic acid calculated as:

(3)Isoelectric point (pI) of basic amino acid is the average of pKa values of two positively charged amine groups in its acidic form. For example pI of lysine calculated as:

Notes: Acidic amino acid has lowest pI value while basic amino acid had highest isoelectric point (pI).
Related topic:

How to calculate Isoelectric point (pI) of acidic and basic amino acids?

Isoelectric point (pI): The hydrogen ion concentration at which a particular amino acid does not influence by electric field is known as Iso-electric point (pI).
At isoelectric points:
(1) [cation] = [Anion]
(2) Net charge on particular amino acid is zero.
(3) Maximum concentration of zwiter ion
(1) Isoelectric point (pI) of neutral amino acid (for example alanine) is the average of pKa1 and pKa2. For example pI of alanine calculated as:
          PI= 1/2(pKa1+pKa2)
(2) Isoelectric point (pI) of acidic amino acid is the average of pKa values of two -COOH groups (uncharged) in its acidic form. For example pI of Glutamic acid calculated as:

(3)Isoelectric point (pI) of basic amino acid is the average of pKa values of two positively charged amine groups in its acidic form. For example pI of lysine calculated as:
Related topic:

Friday, May 14, 2021

How many gram Cu will deposited by passing 2 Amp for 30 minutes in aq solution of CuSO4. What will be weight of O2 produced at anode?


Related Questions:

(1) A current of 2.68 ampere is passed for one hour through an aqueous solution of copper sulphate using copper electrodes. Calculate the change in the mass cathode and that of anode. ( atomic mass of copper is 63.5 u).

(3) On passing 3 faradays of electricity through three electrolytic cells connect in series containing Ag+ , Ca+2 and Al+3 ions respectively , the molar ratio in which three metals ions are liberated at the electrode is