_{}Total energy of (E) of an electron revolving in nth orbit is equal to sum of

**kinetic energy**and

**Potential energy**.

We know the
electron revolve around nucleus due balancing of two forces columbic and
centrifugal forces

This is the
famous Bohr’s equation applicable to Hydrogen like atoms or ions as He

^{+1}, Li^{+2}, Be^{+3}
etc.

The factor
(4 pi epsilon zero) is known as permittivity factor and its numerical value is
1.11268*10

^{-10}C^{2}N^{-1}M^{-2 }( In CGS Unit K= 1)
Pi= 22/7=
3.424, me=9.109 *10

^{-31}kg, e = 1.602 *10^{-10}C and h= 6.626*10^{-34}j-s**Calculation of E**

_{n}in SI Unit:**Bohr’s energy in electron volt:**

We know that,
1eV = 1.602 *10

^{-19}J hence**Energy in term of Rydberg’s Constant:**

**Relation between Total energy (TE), Kinetic energy (KE) and Potential energy (PE):**

**Important conclusions:**

**(1)**The minus sign for the energy of an electron in an orbit represents attraction between the +vely charged nucleus and negatively charged electron.

**(2)**Energy of an electron at infinite distance from the nucleus is zero.

**(3)**As an electron approaches the nucleus, the electrical attraction increases, energy of electron decreases and it becomes negative.

**(4)**Energy of an electron increases as the value of

**‘n’**increases i.e.

**(5)**Value of

**‘n’**remaining unchanged, the amount of energy associated with an electron remains unaltered.

**(6)**Energy of electron in

**first**,

**second**,

**third**and

**fourth**orbit are

**–13.6, –3.4, –1.5, and –0.85 eV**/atom respectively.

**(7)**Although the energy of electron increases with increase in the value of

**‘n’ (orbit),**yet the difference of energy between successive orbits decreases. Thus

**E**etc….

_{2}– E_{1}> E_{3}– E_{2}> E_{4}– E_{3}> E_{5}– E_{4}>,
df

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