The titration of HCl (aq) with a
standardized NaOH solution illustrated the titration of strong acid by a strong
base.
The molecular and net ionic equation
is.
Case (1): At the start point before any titrant has
been added the receiving flask contains only 0.10 M HCl and 50 ml. Because it
is strong acid so
Case (2): After starting but before equivalent point.
Case (3): At equivalent point
Case (4): Before equivalent point
TITRATION SUMMARY TABLE:
| 
   
S.N. 
 | 
  
   
Volume of  
HCl Taken 
 | 
  
   
Volume 
of NaOH 
 | 
  
   
PH 
 | 
  
   | 
 
| 
   
1 
 | 
  
   
50.0 ml (In ml) 
And 0.10 M 
 | 
  
   
0.0 (In ml) 
And 0.10M 
 | 
  
   
1.0 
 | 
  
   | 
 
| 
   
2 
 | 
  
   | 
  
   
10 
 | 
  
   
1.17 
 | 
  
   | 
 
| 
   
3 
 | 
  
   | 
  
   
20 
 | 
  
   
1.36 
 | 
  
   | 
 
| 
   
4 
 | 
  
   | 
  
   
30 
 | 
  
   
1.60 
 | 
  
   
NAVA>NBVB 
 | 
 
| 
   
5 
 | 
  
   | 
  
   
40 
 | 
  
   
1.95 
 | 
  
   | 
 
| 
   
6 
 | 
  
   
(Vertical Over) 
 | 
  
   
45 
 | 
  
   
2.27 
 | 
  
   | 
 
| 
   
7 
 | 
  
   | 
  
   
49 
 | 
  
   
2.99 
 | 
  
   | 
 
| 
   
8 
 | 
  
   
50.0 ml (In ml) 
And 0.10 M 
 | 
  
   
50 
 | 
  
   
7.0 
 | 
  
   
NAVA=NBVB 
 | 
 
| 
   
9 
 | 
  
   | 
  
   
51 
 | 
  
   
11 
 | 
  
   
NAVA<NBVB 
 | 
 
| 
   
10 
 | 
  
   | 
  
   
60 
 | 
  
   
11.95 
 | 
  
   | 
 
GRAPHICAL REPRESENTATION:
ILLUSTRATIVE EXAMPLE: Find the pH of following titrations:
(A) 500 ml, 0.10 M HCl + 500 ml 0.10 M Ca(OH)2
(B) 400 ml, M/200 Ca(OH)2 + 400 ml M/50 HNO3 
 ANSWERS KEY:
(A): PH=12.6989 (B): PH=2.6
(A): PH=12.6989 (B): PH=2.6
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