H2
(g)+Cl2 --> HCl(g)
ΔH= -185KJ/mole
Δng=0
ΔH= ΔU+
ΔngRT
ΔH= ΔU
ΔHR= -185 KJ/mole ,ΔUR=
-185 KJ/mole
H2 (g)+Cl2 --> HCl(g) ΔH= -185KJ/mole
3 mole 3 mole
Hence ΔU= -185 X 3
KJ/Mole
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