Welcome to ChemZipper !!!: Consider the chemical reaction at 300 K H2 (g) + Cl2 --> HCl(g) ΔH= -185KJ/mole calculate ΔU if 3 mole of H2 completely react with 3 mole of Cl2 (g) to form HCl.

Search This Blog

Consider the chemical reaction at 300 K H2 (g) + Cl2 --> HCl(g) ΔH= -185KJ/mole calculate ΔU if 3 mole of H2 completely react with 3 mole of Cl2 (g) to form HCl.

 
                           H2 (g)+Cl2 -->  HCl(g) ΔH= -185KJ/mole
                                       Δng=0
                                   ΔH= ΔU+ ΔngRT
                                  ΔH= ΔU
                       ΔHR= -185 KJ/mole ,ΔUR= -185 KJ/mole
                       H2 (g)+Cl2 --> HCl(g) ΔH= -185KJ/mole
                         3 mole       3 mole
            Hence           ΔU= -185 X 3 KJ/Mole

No comments:

Post a Comment

Top Search Topics