What is the relation between change in enthalpy (dH ) and change in internal (dE) for combustion of methan ?

For the given reaction:

                        CH₄(g) + 2O₂(g) ---------> CO₂(g) + 2H₂O(l)

                                          dH = dE + dnRT

                            Dn = no. of mole of products - no. of moles of reactants = 1– 3 = –2

                                             DH = DE – 2RT