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What is the relation between change in enthalpy (dH ) and change in internal (dE) for combustion of methan ?

For the given reaction:

                        CH4(g) + 2O2(g) ---------> CO2(g) + 2H2O(l)
                                          dH = dE + dnRT
                            Dn = no. of mole of products - no. of moles of reactants = 1– 3 = –2
                                             DH = DE – 2RT

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