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Sunday, August 15, 2021

If covalent radius of A is 0.99 A0 and bond length is 1.46 A0 Calculate the covalent radius of B. XA and XB are 3.5 and 2.5 respectively.

 (A) 0.35 A0              (B) 0.56 A0              (C) 1.98A0               (D) 10.48A0

The covalent radius of B is calculated by the relation given by Stevenson & Schoemaker, given as:

For a diatomic Hetero molecule:

Bond Length (lA-B) = r+ rB- 0.09(XA-XB)

Where XA= Electronegativity of more electronegative atom

Where XB= Electronegativity of less electronegative atom

Bond Length=1.46 A0 = 0.99 A0 + rB - 0.09(3.5-2.5)

 Hence rB = 0.56 A0 


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