List-I contains various reaction sequence and List-II contains different phenolic compounds. Match each entry in List-I with the appropriate entry in List-II and choose the correct option. (IIT Adv 2024 Paper-1)

List-I contains various reaction sequence and List-II contains the possible products. Match each entry in List-I with the appropriate entry in List-II and choose the correct option. (IIT Adv 2024 Paper-1)

 

Among the following complexes, the total number of diamagnetic species is _______. [Mn(NH3)6] 3+, [MnCl6] 3 , [FeF6] 3 , [CoF6] 3 , [Fe(NH3)6] 3+ and [Co(en)3] 3+ [Given, atomic number: Mn = 25, Fe = 26, Co = 27; en = H2NCH2CH2NH2] (IIT Adv 2024 Paper-1)

Among V(CO)6, Cr(CO)5, Mn(CO)5, Fe(CO)5, [Co(CO)3] 3 , [Cr(CO)4] 4 and Ir(CO)3, the total number of species isoelectronic with Ni(CO)4 is _______________. [Given, atomic number: V = 23, Cr = 24, Mn = 25, Fe = 26, Co = 27, Ni = 28, Cu = 29, Ir = 77] ( IIT Ad 2024 Paper-1)

Complete reaction of acetaldehyde with excess formaldehyde, upon heating with conc. NaOH solution, gives P and Q. Compound P does not give Tollen’s test, whereas Q on acidification gives positive Tollen’s test. Treatment of P with excess cyclohexanone in the presence of catalytic amount of p-tolunesulfonic acid (PTSA) gives product R. Sum of the number of methylene groups (-CH2-) and oxygen atoms in R is ________(IITAd 2024 Paper-1).

 

The option(s) in which at least three molecules follow Octet Rule is(are) (Adv 2024 Paper-1)

 

Reaction of iso-propylbenzene with O2 followed by the treatment with H3O + forms phenol and a by product P. Reaction of P with 3 equivalents of Cl2 gives compound Q. Treatement of Q with Ca(OH)2 produces compound R and calcium salt S. The correct statement(s) regarding P, Q, R and S is(are) (IIT Adv 2024 Paper-1)

 

Among the following options, select the option in which each complex in Set-I shows geometrical isomerism and the two complexes in Set-II are ionization isomers of each other. (IIT adv 2024 Paper-1)

 

A closed vessel contains 10 g of an ideal gas X at 300 K, which exerts 2 atm pressure. At the same temperature, 80 g of another ideal gas Y is added to it and the pressure becomes 6 atm. The ratio of root mean square velocities of X and Y at 300 K is (IIT Adv 2024 Paper-1)

 

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid (HNO2) gives the species ( IIT Advanced 2014 paper-1)

 

Aspartame, an artificial sweetener, is a dipeptide aspartyl phenylalanine methyl ester. The structure of aspartame is (JEE (Advanced) 2024 Paper-1)

 

A gas absorbs 100 J of heat and is simultaneously compressed by a constant external pressure of 1.50 atmospheres from a volume of 8 L to 2 L. E will be

 

One mole of an ideal gas at 300Kis expanded isothermally from an initial volume of 1 litre to 10 litres. (R = 2 cal mol^–1 K^–1). E for the process is

 

Calculate the work performed when 2 moles of hydrogen expand isothermally and reversibly at 25ºC from 15 to 50 litres.

 

A gas absorbs 200J of heat and expands against the external pressure of 1.5 atm from a volume of 0.5 litre to 1.0 litre, Calculate the change in internal energy-

 

The internal energy of one mole of a gas is

 

A system does 100J work on surroundings by absorbing 150J of heat. Calculate the change in internal energy-

 

A sample of gas is compressed by an average pressure of 0.50 atmosphere so as to decrease its volume from 400 cm^3 to 200 cm3^.During the process 8.00 J of heat flows out to surroundings. Calculate the change in internal energy of the system.

 

A sample of an ideal gas undergoes a process (4 atm, 40 L) to (1 atm, 150 L). If the internal energy of gas decreases by 10 L-atm, H for the gas is

 

5 moles of an ideal gas (Cp,m= 2/7 R) is heated from 27ºC to 87ºC. The value of H is.

 

90 gm water is completely converted into stream at 100ºC and 1 atm. The internal energy of system (latent heat of vaporisation of water at 100ºC= 540 cal/gm)

 

Two moles of an ideal monoatomic gas is heated from 27ºC to 127ºC.The change internal energy of gas is:

 

500 gm ice at 0ºC is added in 2000 gm water at tºC. If the final temperature of system is 0ºC, then the value of 't' is (latent heat of fusion of ice =80 cal/gm and specific heat capacity of water= 1 cal/gm-ºC)

 

2 moles of an ideal gas absorbs 720 cal heat when heated from 27ºC to 87ºC, at constant volume. 'Cp/Cv' for the gas is :

 

Five moles of a monoatomic ideal gas is heated from 300 K to 400 K at constant pressure. The amount of heat absorbed is :

 

Calculate the amount of heat required to raise the temperature of 50 gm water from 25ºC to 55ºC. Specific heat capacity of water = 4.2 J/ºC-gm.

 

One mole of argon gas (assuming ideal behaviour) is expanded reversibly and adiabatically from 2.5 m^3 at 300K temperature to 5.0 m^3. Cv m for argon is 12.55 JK^–1mol^–1.Calculate the final temperature and pressure of the gas.

 

Two mol of an ideal gas is expanded isothermally and reversibly at 300K to twice the original volume. Calculate q, w, E, and H.

 

Turnbull Blue: Charge transfer from metal to metal: Colour due CTS :

Ferrous (Fe^+2) salt reacts with potassium ferricyanide to form a blue precipitate which is called Turnbull's blue. The reaction is as follows:

 Turnbull Blue: [Fe(II)]3[Fe(III)(CN)₆]2

Charge transfer Spectra (CTS):

Related Question:

(1) Although both [Mn(H2O)6]2+ and [FeF6]3- have a d5 configuration and high-spin complexes. But the dilute solutions of Mn2+ and Fe +3 complexes are therefore colorless. Why?

(2) Which of the Complex of the following pairs has the highest value of CFSE?

(3) Colour of Complexes due to charge transfer:

(4) Why violet colour of [Ti(H2O)6]Cl3 disapear (colourless) on heating heating ? 

(5) Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 although both have +2 oxidation state and 3d*8 configuration ?

(6) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured ? 

(7) Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?

(8) Why all the tetrahedral Complexes are high spin Complexes ?