Acid-base equilibrium in second case shift more towards backward direction. Hence phenol does not react with NaHCO3.
Sunday, January 19, 2020
Why does aqueous sodium bicarbonate solution dissolve carboxylic acids but not phenol though they are also acidic ?
Why enol form of Beta Dicarbonyl compound more stable than those of monocarbonyl compounds?
Enol form of Beta Dicarbonyl compounds are more stable because it has a conjugated π-system and intramolecular H-bonding.
Why enol form of phenol is more stable than its keto isomers?
Which of the Complex of the following pairs has the highest value of CFSE?
(1) [Co(CN)6]3- and [Co(NH3)6]3+
(1) Why all the tetrahedral Complexes are high spin Complexes?
(2) Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?
(3) Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?
(4) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured?
(5) Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 is colour although both have +2 oxidation state and 3d8 configuration ?
(2) [Co(NH3)6]3+ and
[CoF6]3-
(3) [Co(H2O)6]3+ and [Rh(H2O)6]3+
(4) [Co(H2O)6]2+ and [Co(H2O)6]3+
(3) [Co(H2O)6]3+ and [Rh(H2O)6]3+
(4) [Co(H2O)6]2+ and [Co(H2O)6]3+
SOLUTION:
(1) CN is the stronger ligand than NH3 therefore CFSE of [Co(CN)6]3- will be more than [Co(NH3)6]3+
(2) NH3 is stronger ligand than F therefore CFSE of [Co(NH3)6]3+ will be more than [CoF6]3- .
(3) Co belong to 3d series whereas The Rh belong to 4d series. More the value of n more is CFSE therefore CFSE of [Rh(H2O)6]3+ is more than [Co(H2O)6]3+ .
(4) Oxidation number of Co in [Co(H2O)6]3+ is more than the Oxidation number of [Co(H2O)6]2+ therefore, CFSE of [Co(H2O)6]3+ is more than [Co(H2O)6]2+ .
(1) CN is the stronger ligand than NH3 therefore CFSE of [Co(CN)6]3- will be more than [Co(NH3)6]3+
(2) NH3 is stronger ligand than F therefore CFSE of [Co(NH3)6]3+ will be more than [CoF6]3- .
(3) Co belong to 3d series whereas The Rh belong to 4d series. More the value of n more is CFSE therefore CFSE of [Rh(H2O)6]3+ is more than [Co(H2O)6]3+ .
(4) Oxidation number of Co in [Co(H2O)6]3+ is more than the Oxidation number of [Co(H2O)6]2+ therefore, CFSE of [Co(H2O)6]3+ is more than [Co(H2O)6]2+ .
Related
Questions:
(1) Why all the tetrahedral Complexes are high spin Complexes?
(2) Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?
(3) Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?
(4) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured?
(5) Why [Ni(CN)4]-2 is colourless while [Ni(H2O)4]-2 is colour although both have +2 oxidation state and 3d8 configuration ?
Friday, January 17, 2020
How can explain resorcinol (1,3-Dihydroxybenzene) give positive Iodoform test?
Resorcinol (1,3-Dihydroxybenzene) give
positive iodoform test because it is in equilibrium with its tautomer cyclohex-2-en-1,5-dione.
It give 3, 5-dioxohexanoic acid (CH3-CO-CH=CH-CH2-COOH) on reaction with strong base (OH-) (I2+NaOH Iodoform reagent)
,which has a CH3-CO (acetyl) group, so it’ clear that it would be
give positive iodoform test.
How can explain that 1, 3, 5-Trihydroxybenzene give positive iodoform test?
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