What are the structure of CO2 , NO2+ , OCN- , SCN- ?

These molecules are isoelectronic so structure are also similar :

Similar Questions:

How can draw the Lewis Structure of CO?

How can describe the bonding in PF5 using hybrid orbital?

Why does CO form a coordinate bond?

In carbon monoxide molecule carbon and oxygen form a double bond by sharing of two bond pairs , in which 

carbon as well oxygen contributes 2 electrons to each other to form a double bond . 

Now octet of oxygen is completed but carbon is left with two (2) valence electrons and it has a total of six electrons so it's octet is incompleted.

Hence carbon is relatively unstable than oxygen atom because oxygen has nearest noble gas configuration of 8 electrons in their valence shell.

So in order to attain stability oxygen contributes one of its lone pair of electrons to the carbon atom in the formation of a coordinate bond . This leads to completion of octet of both carbon and oxygen .

Important note: 

In coordinate bond a pair of electrons is shared between two atoms but it is contributed by a single atom( Here contributor of lone pair is oxygen atom).

Similar Questions:

How can draw the Lewis Structure of CO?

How can describe the bonding in PF5 using hybrid orbital?

How can draw the Lewis Structure of CO?

The electronic configuration of carbon and oxygen atoms as

C6 =1s2 2s2 2p2
O8 =1s2 2s2 2p4

This information can be used to determine the Lewis Dot Structure of  Carbon monoxide (CO):

Step 1: calculate total valence electrons  for carbon and oxygen atoms.

C = 4
O = 6

Total electrons in CO molecule =10

Step 2: Find octet electrons for each atom , carbon and oxygen

C: 8
O: 8

Total octet electrons =16

Step 3: Find the bonding electrons Subtract total valence electron from total octet electrons

16-10=6 electron (3 bond pair)

Step 4: Find number of bonds between carbon and oxygen atoms  by dividing the number of bonding electrons by 2

6-electrons/2 = 3 bonds

Step 5: The rest are non bonding pairs. Subtract bonding electrons  from valence electrons .

10-6= 4e-= 2 lone pairs

The Lewis structure of CO is identical with that for HC:::CH  except that the C-H bond pair replace by lone pairs.

      "CO is also isoctronic with CN-"

How can describe the bonding in PF5 using hybrid orbital?

The electron-pair and molecular geometry oF PF5 are trigonal-bipyra- midal according to its Lewis structurc and VSEPR theory. Five covalent bonds must point to the corners of a trigonal bipyramid. Therefore, the P atom must  have a single electron in each of five hybrid orbitals. the hybrid scheme is  Sp3d is required.  

Each of the five P-F sigma bond involves overlap of one of the phosphorus spec hybrid orbital with fluorine 2p orbital.

What is Arrhenius equation ?

The temperature dependence of rate of a chemical reaction can be accurately explained by Arrhenius equation. It was first proposed by Dutch chemist   J.H. Vant’s Hoff but Swedish chemist Arrhenius provides its physical justification and interpretation.

Where  

 K= Rate constant

 A= Arrhenius constant or frequency factor or pre exponential factor

 R= Universal gas constant =25/3 joule per mole per second

Ea= Activation Energy

 T= temperature

-Ea/RT= Boltzmann factor or fraction of molecule having equal or greater than Activation energy or fraction of molecule that have kinetic energy greater than activation energy.

Related Questions:

(1) What is Arrhenius equation ?

(2) what happen when activation energy of a chemical reaction becomes equal to RT?

(3) What is the activation energy and how to different from threshold energy ?

(4) In Arrhenius equation for a certain reaction, the value of A and Ea (activation energy) are 4 × 10^13 sec–1 and 98.6 kJ mol–1 respectively. At what temperature, the reaction will have specific rate constant 1.1 × 10^–3 sec–1?

(5) The energy of activation for a reaction is 100 kJ mol–1. Presence of a catalyst lowers the energy of activation by 75%.What will be effect on rate of reaction at 20ºC, other things being equal?

(6) A drug becomes ineffective after 30 % decomposition. The original concentration of a sample was 5mg/mL which becomes 4.2 mg/mL during 20 months. Assuming the decomposition of first order , calculate the expiry time of the drug in months. What is the half life of the product?

(7) A first order reaction is 20 % completed in 10 minutes. Calculate the time taken for the reaction to go to 80 % completion. 

(8) The rate of a reaction triple when temperature changes from 20”C to 50”C. Calculate energy of activation for the reaction (R = 8.314 JK^1 mol^1).