Welcome to Chem Zipper.com......

Search This Blog

Friday, December 25, 2020

How to determine order of bond angle of Me-O-Me, H3Si-O-SiH3 and (ph)3Si-O-Si(Ph) ?

 (1) Oxygen of Me-O-Me is sp3 hybridised so C-O-C bond angle is more than 109’28” approx 110” due to crowding of methyl group.

(2) In disilyl ether , oxygen is Sp2 hybridised and planer due to back bonding between oxygen and silicon atom.  In this back bonding lone pair of oxygen atom donate to the vacant d orbital of silicon atom  due to this fact bond lengths of Si-O is decrease and  increases (approx 140”).

(3) In (Ph)3Si-O-Si(Ph)3  compounds Si-O-Si bond angle is Approx 180 due to back bonding and hybridisation is Sp.


Related Questions:

Why trimethylamine amine ( N(CH3)3) is tetrahedral while trisilyl amine (N(SiH3)3) planner.?









How to compared bond angle (C-N-C) and (Si-N-Si) in trimethyl amine and trisilyl amine respectively?

Nitrogen (N) atom in trimethyl amine [N(CH3)3] is sp3 hybridised and tetrahedral ( bond angle ~107)  due to non bonding electron pair of N is localised (more basic). On the other hand N atom of trisilyl amine [N(SiH3)3] is sp2 hybridised and trigonal planner (bond angle~120).This is due to the participation of non-bondlng pair of N into pπ-dπ back banding. Due to this delocalization of non-bonding electron pair of N in trisilyl amine it is also less basic

Related Questions:

Why trimethylamine amine ( N(CH3)3) is tetrahedral while trisilyl amine (N(SiH3)3) planner.?









What is structure (CF3)2-Al-O-Al-(CF3)2 and also find the number of pi bond or Back bond?

Thursday, December 24, 2020

What is structure (CF3)2-Al-O-Al-(CF3)2 and also find the number of pi bond or Back bond?

Generally neutral atom donates only one lone pair to back bonding because after that, electron density on that atom itself highly reduced but the compound [(CF3)2-Al-O-Al-(CF3)2] is a rare example of two lone pair donation.

Related Questions:

Why trimethylamine amine ( N(CH3)3) is tetrahedral while trisilyl amine (N(SiH3)3) planner.?









What are the structure of (1) N(SiH3)3 (2) {(Me)3Si}2N-Si(Me)3 (3) HN(SiH3)2 and give the Answers of following questions?

 

Q (1): which is greater x or y?
Q (2): which is greater x or z?
Q (3): which have greater extent of back Bonding?

SOLUTION:

Ans: (1): ‘y’ is greater than ‘x’ because of steric repulsion of -CH3 group.

Ans: (2): “z’ will be greater because one lone pair going two places.

Ans; (3): the extant of back bonding is 3rd >1st > 2nd 

Which of the following is correct order of (B-O) bond length of following compounds? (1) B(OH)3 (2) B(OMe)3 and (3) B(Me)2OH

 SOLUTION:


Extent Back Bonding is   3>1>2 and bond length order is  y>x>z  

Related Questions: