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Sunday, April 24, 2022

Explain the formation of Na4[Fe(CN)6] and Na4[FeF6] ? Show which is low spin and which is high spin complex and also calculate the Crystal field stablisation energy (CFSE) ?

In the given compounds CN– is strong field ligands and F– is weak field ligand and in both compounds ions is in +2 oxidation state d6 configuration.

What are bridging ligands and how to show bridging ligands in naming, explain with suitable example.

(A) If a complex ion has two or more than two metal atoms then it is termed polynuclear. The ligand which connects the two metal ions is called as Bridging ligand or Bridge group.
(B) A prefix of Greek letter (U) , is repeated before the name of each different kind of bridging group.

Friday, April 22, 2022

[Fe(CN)6]3- is weakly paramagnetic while [Fe(CN)6]4- is diamagnetic, why ?


[Fe(CN)6]3- involves  d2sp3  hybridization

Related Questions;

[Fe(CN)6]4- is diamagentic while [FeF6]4- is strongly paramagnetic.Why ?

CN- is strong field ligand and so it pairs up the electrons leading to the formation of low spin complex which is diamagnetic. [Fe(CN)6]4-

Which of the Complex of the following pairs has the largest value of CFSE?


(1) [Co(CN)6]3-  and [Co(NH3)6]3+
(2) [Co(NH3)6]3+ and [CoF6]3-
(3) [Co(H2O)6]3+  and [Rh(H2O)6]3+
(4) [Co(H2O)6]2+ and [Co(H2O)6]3+

SOLUTION:

(1)
  CN is the stronger ligand than NH3 therefore CFSE of [Co(CN)6]3-  will be more than  [Co(NH3)6]3+
(2) NH3 is stronger ligand than F therefore CFSE of [Co(NH3)6]3+ will be more than [CoF6]3- .
(3) Co belong to 3d series whereas The Rh belong to 4d series. More the value of n more is CFSE therefore CFSE of  [Rh(H2O)6]3+  is more than [Co(H2O)6]3+ .
(4) Oxidation number of Co in [Co(H2O)6]3+ is more than the Oxidation number of [Co(H2O)6]2+  therefore, CFSE of [Co(H2O)6]3+ is more than  [Co(H2O)6]2+ .