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What is product obtained when N2O5 is treated with NaCl?


When N2O5 is treated with NaCl with NaCl solution then ionic reaction occurs and NaNO3 and NO2Cl is formed.
          N2O5 + NaCl --> NaNO3 + NO2Cl
This reaction proves that solid N2O5 is in ionic nature.
          N2O5(s) ---->[ NO2]+  + [NO3]-
N2O5 is a rare example of a compound that adopt two structure depending on the conditions most commonly it is a salt, but under some conditions it is a polar molecule.
            [NO2]+ [NO3]- = [N2O5]

Related Questions:


Which is more basic N(CH3)3 or N(SiH3)3 , explain?


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