In Cupper Sulphate pentahydrate (CuSO4.5H2O) Cu is coordinated with 4 water molecules and two more oxygen atoms from Sulphate ion. And hence the coordination number of Cu (II) ion is six and hybridization is sp3d2 with distorted octahedral geometry. Now fifth water molecule is hydrogen bonded and is deeply embedded in crystal.
Thus it is clear that four (4) water molecules are coordinated and one (fifth one) water molecule is bonded with hydrogen bond. And its formula also written as [Cu(H2O )4SO4].H2OReleted Questions:
(1) What is the structure of Blue vitriol (CuSO4) .5H2O
also represent the H-Bond with water molecules?
(2) Why bond angle of hydrides of
group 15, decreases down the group?
(3) Why SF6 behave inert towards
hydrolysis?
(4) What are the SESQUI OXIDES ?
give the examples.
(5) Arrange in increasing order of
extent of hydrolysis [ CCI4, MgCI2, AICI3, PCl5, SiCI4].
(6) Why SF6 behave inert towards
hydrolysis?
(7) Although Sulphur contain
vacant d-orbital but SF6 does not under go hydrolysis. Why ?
(8) Phosphorus can form PCl5 but
nitrogen can not form NCl5 why?
(9) Why PCl3 hydrolysed while NCl3
can not be hydrolysed?
(10) CCl4 can not be hydrolysed but
SiCl4 can be. Why?
(11) Silianol (SiH3OH) is more acidic than methanol (CH3OH) why?
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