How many molecules form coordinate bonds in CuSO4.5H2O?

In Cupper Sulphate pentahydrate (CuSO₄.5H₂O) Cu is coordinated with 4 water molecules and two more oxygen atoms from Sulphate ion. And hence the coordination number of Cu (II) ion is six and hybridization is sp3d2 with distorted octahedral geometry. Now fifth water molecule is hydrogen bonded and is deeply embedded in crystal.

Thus it is clear that four (4) water molecules are coordinated and one (fifth one) water molecule is bonded with hydrogen bond. And its formula also written as [Cu(H₂O )₄SO₄].H₂O

Releted Questions:

(1) What is the structure of Blue vitriol (CuSO4) .5H2O also represent the H-Bond with water molecules?

(2) Why bond angle of hydrides of group 15, decreases down the group?

(3) Why SF6 behave inert towards hydrolysis?

(4) What are the SESQUI OXIDES ? give the examples.

(5) Arrange in increasing order of extent of hydrolysis [ CCI4, MgCI2, AICI3, PCl5, SiCI4].

(6) Why SF6 behave inert towards hydrolysis?

(7) Although Sulphur contain vacant d-orbital but SF6 does not under go hydrolysis. Why ?

(8) Phosphorus can form PCl5 but nitrogen can not form NCl5 why?

(9) Why PCl3 hydrolysed while NCl3 can not be hydrolysed?

(10) CCl4 can not be hydrolysed but SiCl4 can be. Why?

(11) Silianol (SiH3OH) is more acidic than methanol (CH3OH) why?

(12) How many hydrogen bonded water molecules does CuSO4.5H2O have?