Given compounds are...
(A) [Co(NH3)6]3+
(B) [Rh(NH3)6]3+
(C) [Ir(NH3)6]3+
Solution :
In given compounds number of ligands, types of ligands and oxidation state is same for central atom belongs to same group but different transition series 3d, 4d and 5d respectively. We know that as move top to bottom size of d-orbital(3d--> 4d --> 5d) is increases so ligand approches to d-orbitals more closely so the repulsion
between d-orbital of metal and ligand is high and splitting energy increases.order of splitting energy [Co(NH3)6]3+ < [Rh(NH3)6]3 <[Ir(NH3)6]3+
Related Questions:
(1) What are bridging ligands and how to show bridging ligands in naming, explain with suitable example.
