Mole concept and Stiochiometry:

 (1) SOME BASIC CONCEPT OF CHEMISTRY:
(1) BASIC TOPICS :
1.1.1 DALTON'S ATOMIC THEORY:
1.1.2 ATOMIC MASS AND MOLECULAR MASS:
1.1.3 PERCENTAGE COMPOSITION OF COMPOUNDS:
1.1.4 DETERMINATION OF EMPIRICAL AND MF:
(2) Mole concept and Stiochiometry
2.1.1 MOLE-MOLE ANALYSIS
2.1.2 CONCEPT OF LIMITING REAGENTS
2.1.3 PRINCIPLE OF ATOM CONSERVATION (PAOC)
2.1.4 GRAVIMETRY-WEIGHT WEIGHT ANALYSIS
2.1.5 EUDIOMETRY-VOLUME VOLUME ANALYSIS OF GAS
2.1.6 DEGREE OF HARDNESS OF HARD WATER
2.1.7 OLEUM AND ITS PERCENTAGE(%) LABBELING
2.1.8 VOLUME STRENGTH OF H2O2(aq)
2.1.9 PERCENTAGE (%) AVAILABLE CHLORINE IN BLEACHING POWDER
2.1.10 PERCENTAGE YIELD OF CHEMICAL REACTION:
2.1.11 PERCENTAGE PURITY OF GIVEN SAMPLE:
(3) law of chemical combinations:
3.12 (1) Law of conservation of mass: 

3.12 (2) Law of constant composition 

3.12 (3) Law of multiple proportion:

3.12 (4) Law of reciprocal proportion:

 

3.12 (5) Gay Lussac’s law of Combining Volumes:

 Related Questions:

(1):Calculate the mole fraction of solute in the 12 molal aqueous solution of CaCO3.

(2):The mole fraction of glucose in aqueous solution is 0.2 , The molality of solution will be.

(3):If the mole fraction of a solute is changed from 1/4 to 1/2 in the 800 gm of solvent . then the ratio of molality will be .

(4):Mole fraction of I2 (iodine) in benzene (C6H6) is 0.2 . Calculate the molality of iodine (I2) in benzene.

(5):Calculate the amount of water that should be added to 16 gm methanol to make mole fraction of methanol as 0.25.?

(6) What is relation between mole fraction and molality of solute ?

 

25 ml of household bleach solution was mixed with 30 ml of 0.50 M KI and 10 ml of 4.0N acetic acid. In this titration of the liberated iodine 48 ml of 0.25 N Na2S2O3 was used to reach the end point. The Molarity of household bleach solution is?

Calculate the % of available chlorine in the sample in a sample of 3.35 gm of bleaching powder which was dissolved to 100 ml water. 25 ml of this solution on treatment react with KI and dilute acid. Required 20 ml 0.125 N Hypo solution (Sodiumthiosulphate- Na2S2O3).

Related Questions:

(1) What are the Antichlor ?

(2) If 4 gm of bleaching powder dissolved to give 100 ml solution 25 ml of it react with excess of CH3COOH and KI .The Iodine liberation required 10 ml of 0.125 N Hypo solutions. Calculate % of available chlorine in the sample.

PERCENTAGE (%) AVAILABLE CHLORINE IN BLEACHING POWDER:

 

What are the Antichlor ?

An antichlor  is a substance used to decompose residual hypochlorite or chlorine after use of chlorine based bleaching , in order to prevent ongoing reactions .example s of antichlor – Sodiumbisulphite (NaHSO₃), Pottassiumbisulphite (KHSO₃) ,  Sodiummetasulphite (Na₂S₂O₃), Sodiumthiosulphate  (Na₂S₂O₃) and hydrogen peroxide (H₂O₂).

If trace of chlorine are not remove from pulp used for paper manufacturing,then on the long standing it weaken the paper and makes it yellowish. 

Related topics: 

Mole concept and Stiochiometry

MOLE-MOLE ANALYSIS

 CONCEPT OF LIMITING REAGENTS 

GRAVIMETRY-WEIGHT WEIGHT ANALYSIS

 OLEUM AND ITS PERCENTAGE(%) LABBELING

VOLUME STRENGTH OF H2O2(aq) 

 PRINCIPLE OF ATOM CONSERVATION (PAOC) 

 GRAVIMETRY-WEIGHT WEIGHT ANALYSIS 

EUDIOMETRY-VOLUME VOLUME ANALYSIS OF GAS 

DEGREE OF HARDNESS OF HARD WATER 

PERCENTAGE YIELD OF CHEMICAL REACTION: 

PERCENTAGE PURITY OF GIVEN SAMPLE:

PERCENTAGE (%) AVAILABLE CHLORINE IN BLEACHING POWDER:

 

 

If 4 gm of bleaching powder dissolved to give 100 ml solution 25 ml of it react with excess of CH3COOH and KI .The Iodine liberation required 10 ml of 0.125 N Hypo solutions. Calculate % of available chlorine in the sample.

Available chlorine in sample of bleaching powder can be calculated as per the following reactions.