A closed tank has two compartments A and B, both filled with oxygen (assumed to be ideal gas). The partition separating the two compartments is fixed and is a perfect heat insulator (Figure 1). If the old partition is replaced by a new partition which can slide and conduct heat but does not allow the gas to leak across (Figure 2), the volume (in m3) of the compartment A after the system attains equilibrium is--- (IIT-Ad-2018)

Total volume of compartment A and B

 V_A+V_B = 4m³…………………………………….................................(1)

According to question partition do not allow gas leak between compartment (A) and compartment (B) so number of moles after and before inserting new partition which can slide.

So number of moles in compartment (A) and compartment (B)

n_A=PxV_A/RT=1m³x5 bar/400 K  ……………………………………… (2)

n_B=PxV_B/RT=3m³x1 bar/300 K  ………………………………………. (3)

Equation (2)/ (3)

Get V_A/V_B=5/4   Or  V_A=5V_B/4 ………………………………………..(4)

Put the value of V_A   from equation (4) to in equation (1) and find the value of V_A  after placing frictionless slider.

5V_B/4 +V_B = 4m³        => V_B = 16/9m³       and  V_A = 20/9m³   =2.22  m³  or L

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1 mole of N2 and 3 moles of H2 are mixed in 8.21 lit. container at 300 K to form NH3 . If at equilibrium, average molecular mass was found to be 34/3, then find partial pressure of each component.

A vessel of 2 lit. capacity contains hydrogen at 380 mm pressure at 27°C. 16 gm of O2 is added to the container at constant temperature, then find the final total pressure and final partial pressure of H2 . Sol. As partial pressure of a gas is independent from the pressure of other gas, initial as well as final partial pressue of H2 gas,

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What is product of reaction between diborane (B2H6) and ammmonia (NH3)?

 

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STRUCTURE OF BORON NITRIDE:

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STRUCTURE OF DIBORANE :

BORIC ACID (H3BO3) :

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A plant virus is found to consist to uniform cylindrical particles of 150Å in diameter and 5000Å long. The specific volume of the virus is 0.75 cm3/g. What is the molecular mass of virus ?

 

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Initially when tube is horizontal then pressure (P) =76 cm Hg and volume (V) =45 cm of tube.

Finally when tube is made vertical, as temperature and pressure are constant, then by gas law

P₁ (45+x)=PV   ……..(1)

(P₁+10)(45-x) =PV……(2)

From equations 1 and 2 find the value of P₁

P₁ =(225-5x)/x

Put the value of P₁ in equation 1 or 2

On calculating the value of x is 2.95 cm

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The Molecular weight (M_A) of N₂O (laughing gas = 44 gm/mol.

Molecular weight (M_B) of (C₁₀H₅ClN₂) (Tear gas) = 179 gm/mol.

(r₁/r₂) = √{ (M_B/M_A) }

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Therefore:

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Therefore, from 20^th row where students will start weeping and laughing simultaneously.

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