CN- is strong field ligand and so it pairs up the electrons leading to the formation of low spin complex which is diamagnetic. [Fe(CN)6]4-
Friday, April 22, 2022
Which of the Complex of the following pairs has the largest value of CFSE?
(1) [Co(CN)6]3- and [Co(NH3)6]3+
(2) [Co(NH3)6]3+ and [CoF6]3-
(3) [Co(H2O)6]3+ and [Rh(H2O)6]3+
(4) [Co(H2O)6]2+ and [Co(H2O)6]3+
SOLUTION:
(1) CN is the stronger ligand than NH3 therefore CFSE of [Co(CN)6]3- will be more than [Co(NH3)6]3+
(2) NH3 is stronger ligand than F therefore CFSE of [Co(NH3)6]3+ will be more than [CoF6]3- .
(3) Co belong to 3d series whereas The Rh belong to 4d series. More the value of n more is CFSE therefore CFSE of [Rh(H2O)6]3+ is more than [Co(H2O)6]3+ .
(4) Oxidation number of Co in [Co(H2O)6]3+ is more than the Oxidation number of [Co(H2O)6]2+ therefore, CFSE of [Co(H2O)6]3+ is more than [Co(H2O)6]2+ .
Saturday, April 16, 2022
Compare the splitting energy (CFSE) into the following compound and give appropritate reason ? [Co(NH3) 6] 3+ , [Rh(NH3) 6] 3+,[Ir(NH3) 6] 3+
In given compounds number of ligands, types of ligands and oxidation state is same for central atom belive to same group but different transition series 3d, 4d and 5d respectively. We know that as move top to bottom size of d-orbital(3d--> 4d -->5d) is increases so ligand approches to d-orbitals more closely so the repulsion between d-orbital of metal and ligand is high and splitting energy increases.
Thus order of splitting energy
[Co(NH3)6]3+ < [Rh(NH3)6]3+ < [Ir(NH3)6]3+
Related questions:
(4) What is denticity of NO and NO+ ligands ?
(5) Why all the tetrahedral Complexes are high spin Complexes?
(6)Why Fe(CO)5 is colourless while Fe(bipy)(CO)3 is intensely purple in colour ?
(7) Why [Mn(H2O)6]+2 is colourless although in which Mn+2 ion had five unpaired electrons ?
(8) Why [FeF6]3– is colourless whereas [CoF6]3– is coloured?
Which is correct statement for regarding I2Cl6 molecule?
(B) 8 Number of angles of type 02 are present
(C) 03 > 01 > 02
(D) Total 4 unshared lone pairs are present
Ans key (A)
What is structure and also explain the bridge bonding of I2Cl6 ?Related Questions:
(1) What is the difference between the structure of AlCl3 and diborane?
Thursday, April 14, 2022
Ellingham Diagram and it's features:
The changes in Gibbs energy that occur when one moleofoxygen isused may be plotted against temperature for a number of reaction of metals to form
their oxides. Such a graph is shown in Figure below and is called an Ellingham diagram for oxides. Similarly, we can plot Ellingham diagrams for halides.
(1) Ellingham diagram normallyconsist of plots of dfG° vs T for the formation of oxides of elements, i.e. for the reaction.
(2) The graphs for metal oxide all slope upwards because the change in Gibbs energybecomes less negative with increase in temperature.
(3) Each plot follows a straight line unless there is some change in phase.
(4) When the temperature is increased, a point will be reached when the line crosses dG = 0 line. Below this temperature the dfG° of oxide is negative and hence the oxide is stable.Above this temperature dfG° of the oxide is positive and hence the oxide becomes unstable and decomposes on its own into metal and oxygen.
Chemical refining methods:
(2) Parting Process:
(6) Vapour phase refining:
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