No, We know that Gabriel phthalimide reaction requires the treatment of potassium phthalimide with C6H5Cl or C6H5Br. Since aryl halides do not undergo nucleophilic substitution under ordinary laboratory conditions, therefore C6H5Cl or C6H5Br does not react withbpotassium phthalimide to give N – phenylphthalimide and hence aniline cannot be prepared by this method.
Search This Blog
Subscribe to:
Post Comments (Atom)
Featured Post
STRUCTURE OF FULLERENCES :
(1) A fascinating discovery was the synthesis of spherical carbon-cage molecules called fullerences. The discovery of fullerene was awarde...
Top Search Topics
-
Bleaching powder is not a true compound but it is a mixed salt of calcium hypochlorite [Ca (OCl) 2 ].3H 2 O and basic calcium chloride [C... -
The structure of crystalline solids is determined by packing of their constituents .In order to understand the packing of the constituen... -
(1) Back bonding is a type of weaker π bond which is formed by sideways overlapping of filled orbital with empty orbital present on adjace... -
Phosphorous is a pentavalent element hence show +3 and +5 oxidation state (d orbital presence).it form two oxide P 2 O 3 (+3) and P 2 O 5... -
We know that the Ligands which cause large degree of crystal filed splitting are termed as strong field ligands. and Ligands that cause onl... -
(1) Oleum can be represented by the formula ySO 3 .H 2 O where y is the total molar sulphur trioxide content .the value of y can be va... -
Pyrrole, furan and thiophene undergo electrophilic substitution reactions like nitration, sulphonation, halogenation etc. characteristic ... -
In case of Pyrrole the lone pair electrons of the nitrogen atom is involved in conjugated system of pi electrons of five membered ring ... -
[FeF 6 ] 3- is a Fe (III) complex hence [Ar] 3d 5 . F - is a weak field ligand and the complex is high spin: ... -
Tetahedral complex (sp 3 ): In a tetrahedral field : Consider a cube such that a metal atom or ion is situated at its centre of symmetry ...
No comments:
Post a Comment